Question #2b3b7

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Question #2b3b7

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Answer 1 · 2017-07-09T20:16:08

14.3 days

Explanation:

Since we know the $half life$ $"half life"$ of $Phosphorus-32$ $"Phosphorus-32"$ is $14.3 days$ $"14.3 days"$ and the definition of half life is the the amount of time it takes for the initial sample to decay to half its amount, then we also can establish the following:

$- - - - 1 gram . decays - -- \to 0.5 grams = 1 half life has occurred$ $color(white)(----)color(blue)["1 gram"color(white)(.)stackrel"decays"-> "0.5 grams = 1 half life has occurred"$

and since $1 half life = 14.3 days$ $color(red)["1 half life = 14.3 days"$ , it would take about $14.3 days$ $color(red)["14.3 days"$ for the initial sample to decay to half its amount.

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Question #2b3b7

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