Question #93462

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Question #93462

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Answer 1 · 2017-07-18T18:47:19

$λ \approx 2.857 m$ $lambda ~~ 2.857" m"$

Explanation:

Starting with the equation:

$C = λ f$ $C = lambdaf$

We solve the equation for the wavelength, $λ$ $lambda$ :

$λ = \frac{C}{f}$ $lambda = C/f$

We are given the frequency, $f = 105 \times 10^{6} Hz$ $f = 105xx10^6" Hz"$ and we know the speed of light, $C = 3.0 \times 10^{8} m/s$ $C = 3.0xx10^8" m/s"$

$λ = \frac{3.0 \times 10^{8} m/s}{105 \times 10^{6} Hz}$ $lambda = (3.0xx10^8" m/s")/(105xx10^6" Hz")$

$λ \approx 2.857 m$ $lambda ~~ 2.857" m"$

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Question #93462

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