What mass of calcium carbide, $C a^{2 +} C \equiv C^{2 -}$ $Ca^(2+)C-=C^(2-)$ will give a $1.12 \cdot L$ $1.12*L$ volume of acetylene gas upon treatment with water?

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What mass of calcium carbide, $C a^{2 +} C \equiv C^{2 -}$ $Ca^(2+)C-=C^(2-)$ will give a $1.12 \cdot L$ $1.12*L$ volume of acetylene gas upon treatment with water?

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Answer 1 · 2017-07-19T16:46:49

Well, you need to specify your conditions...we follow the stoichiometric equation....

$C a^{2 +} {C \equiv C}^{2 -} + 2 H_{2} O \to H C \equiv C H (g) ↑ ⏐ ⏐ + C a {(O H)}_{2}$ $Ca^(2+){C-=C}^(2-) + 2H_2O rarr HC-=CH(g)uarr+ Ca(OH)_2$

Explanation:

It is a fact that $1 mole$ $"1 mole"$ of $Ideal Gas$ $"Ideal Gas"$ occupies $25.4 \cdot L$ $25.4*L$ under standard conditions. You will have to check your syllabus, because standards vary across curricula........especially these days.

We assume ideality, and thus, since moles of acetylene are equivalent to moles of calcium carbide, we need a mass..........

$\frac{1.12 \cdot L}{25.4 \cdot L \cdot m o l^{- 1}} \times 64.1 \cdot g \cdot m o l^{- 1} \equiv 2.83 \cdot g$ $(1.12*L)/(25.4*L*mol^-1)xx64.1*g*mol^-1-=2.83*g$

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What mass of calcium carbide, $C a^{2 +} C \equiv C^{2 -}$ $Ca^(2+)C-=C^(2-)$ will give a $1.12 \cdot L$ $1.12*L$ volume of acetylene gas upon treatment with water?

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What mass of calcium carbide, Ca2+C≡C2−Ca^(2+)C-=C^(2-) will give a 1.12⋅L1.12*L volume of acetylene gas upon treatment with water?

1 Answer

Explanation:

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What mass of calcium carbide, $C a^{2 +} C \equiv C^{2 -}$ $Ca^(2+)C-=C^(2-)$ will give a $1.12 \cdot L$ $1.12*L$ volume of acetylene gas upon treatment with water?