Question

A `30*L` volume of carbon monoxide is reacted with a `10*L` volume of oxygen gas. How much carbon monoxide remains unreacted?

Answer 1

This question needs a bit of work.......

Explanation:

You have the stoichiometric equation......

`CO(g) + 1/2O_2(g) rarr CO_2(g)`

Under equivalent conditions of temperature and pressure, `Vpropn`, where `n="number of moles"....`

And thus you have `30*L` of carbon monoxide, and LESS than ONE EQUIV of dioxygen, i.e. a `10*L` volume rather than a `15*L` volume. WE assume that the dioxygen reacts quantitatively with `20*L` of `CO` to give `20*L` of `CO_2`, leaving `10*L` `CO` UNREACTED.