Question

Question #b7690

Answer 1

`lim_(x->oo) x^2cos(1/x) = +oo`

Explanation:

Substitute `y=1/x`. When `x->oo`, `y->0^+`, so:

`lim_(x->oo) x^2cos(1/x) = lim_(y->0^+) cosy/y^2 = oo`

graph{x^2cos(1/x) [-10, 10, -5, 5]}