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Answer 1 · 2017-08-11T12:26:03

The exponential growth equation is $p (t) = p (0) \cdot e^{(0.328418) \cdot t}$ $p(t) = p(0)* e ^((0.328418)*t)$

$p (0) = 34; p (12) = 1750$ $p(0) =34 ; p(12) =1750$ , exponential growth equation

is $P(12) = p(0) * e ^(kt) ; t =12 :. e^(k*12) = (p(12))/(p(0))$

Taking natural log on both sides we get

$k*t = ln ((p(12))/(p(0)))= ln (1750/34); (ln e) =1$

or $12k = ln (1750/34) or k = ln (1750/34) /12 = 0.328418$

So the exponential growth equation is $p(t) = p(0)* e ^((0.328418)*t)$

. where $p(0)$ is population at time $t=0$ and

$p(t)$ is population at time $t$ . [Ans]