Question

Can we use fractional coefficients in stoichiometric equations?

Is `H_2(g) + 1/2O_2(g) rarr H_2O(l)` correct?

Answer 1

So you ask about half-integral coefficients.....? Can you use them? I dunno, ask your chemistry professor. If he/she uses them on the whiteboard I would say yes....

Explanation:

So is `H_2(g) + 1/2O_2(g) rarr H_2O(l)` right?

Now I cannot have HALF a dioxygen molecule, but I certainly can have half a mole, i.e. a `16*g` mass of dioxygen. And this combines with a mole of dihydrogen, i.e. a `2*g` mass of `H_2`, to give a molar quantity of water, i.e. an `18*g` mass of water.

The stoichiometric coefficients used in the given equation are thus no more than tools. They may be appropriate or inappropriate given a specific scenario. When we assess stoichiometric equivalence, I maintain that a half-integral coefficient can certainly be useful, and correct, and therefore right. And, for me at least, when we write out the alternative.....

`2H_2(g) + O_2(g) rarr 2H_2O(l)`

....when we calculate equivalent masses, there is the possibility of ballsing something up. Do I divide by two, or do I multiply by two...to find mass equivalence? And still, after many years, it is NOT immediately obvious to me.....on the other hand...for...

`H_2(g) + 1/2O_2(g) rarr H_2O(l)`

..the mass equivalence is directly obvious to me.

We know that all chemical equations observe [stoichiometry.](https://socratic.org/questions/how-to-balance-equation-in-chemistry)

And the answer to your question is that by the criteria I have advanced.....`H_2(g) + 1/2O_2(g) rarr H_2O(l)` IS RIGHT! They are a means to an end to represent stoichiometry, i.e. conservation of mass and charge. The equation is there to serve me, to help me in calculating stoichiometric equivalence. I am not here to serve some abstract notion of chemical equations.

Likewise.....`HC-=CH(g) +5/2O_2(g)rarr 2CO_2(g) +H_2O(l)` is also correct, as is...

`C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l)` because the representation absolutely CONSERVES MASS and CHARGE. Happy? Not everyone will be.