What is the de Broglie wavelength for an electron that travels at 90% the speed of light?
1 Answer
Aug 29, 2017
See below
Explanation:
First we need to know the formula. It is,
we know speed of light is
To find that we do this,
0.90c = 3.00 xx 10^8 "m/s" xx 0.90
=2.7 xx 10^8 "m"//"s"
λ = h/(mv)
λ= wavelength
h= Planck's constant, which is6.63 xx 10^-34 "m"^2 cdot "kg"//"s"
m= mass of electron, which9.11 xx 10^-31 "kg"
v= velocity
lambda =(6.63 xx 10^-34 "kg"cdot"m"^2//"s") / ((9.11xx10^-31 "kg") xx (2.7xx10^8 "m/s"))
=> lambda= 2.70 xx 10^-12"m"