Question #96eae

1 Answer
Sep 3, 2017

Well, we know that c=nuxxlambda..........

Explanation:

And so lambda("wavelength")=c/nu...and so we put the numbers into this quotient.....

lambda=(3.00xx10^8*m*s^-1)/(3.64xx10^7*s^-1)

(Note "Hz"-="frequency" and has units of s^-1)

And so we get.....lambda=8.24*m....i.e. we are in the radiowave section.