Question #e7a7d

1 Answer
Sep 15, 2017

Here's what I got.

Explanation:

For a given radioactive isotope, the nuclear half-life, t_"1/2", tells you the time needed for half of an initial sample of this isotope to undergo radioactive decay.

This means that with every half-life that passes, the mass of the sample will be halved.

![www.schoolphysics.co.uk)

In your case, you know that the isotope has a half-life of "120 s". If you start with an "80-g" sample, you will end up with

  • "80 g" * 1/2 = "80 g"/2^color(red)(1) -> after color(red)(1) half-life passes
  • "80 g"/2^color(red)(1) * 1/2 = "80 g"/2^color(red)(2) -> after color(red)(2) half-lives pass
  • "80 g"/2^color(red)(2) * 1/2 = "80 g"/2^color(red)(3) -> after color(red)(3) half-lives pass
    vdots

and so on. You can thus say that your sample will contain

  • "After 120 s"

(120 color(red)(cancel(color(black)("s"))))/(120 color(red)(cancel(color(black)("s")))) = color(red)(1) implies "80 g"/2^color(red)(1) = "40 g"

  • "After 240 s"

(240 color(red)(cancel(color(black)("s"))))/(120 color(red)(cancel(color(black)("s")))) = color(red)(2) implies "80 g"/2^color(red)(2) = "20 g"

  • "After 480 s"

(480 color(red)(cancel(color(black)("s"))))/(120 color(red)(cancel(color(black)("s")))) = color(red)(3) implies "80 g"/2^color(red)(3) = "10 g"