If a $10 \cdot m L$ $10*mL$ volume of nitrogen gas reacts with stoichiometric hydrogen, what is the likely volume of ammonia gas produced?

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Answer 1 · 2017-09-15T15:16:36

$\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) ⇌ N H_{3} (g)$ $1/2N_2(g)+3/2H_2(g) rightleftharpoons NH_3(g)$

Would it not be $20 \cdot m L$ $20*mL$ ?

Of course, we have assumed stoichiometric reaction (the which is very unlikely)......

While the stoichiometric coefficients relate to moles NOT volume, given constant temperature and pressure, VOLUME is proportional to number of moles.

If a 10⋅mL10*mL volume of nitrogen gas reacts with stoichiometric hydrogen, what is the likely volume of ammonia gas produced?