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Answer 1 · 2018-01-30T14:00:15

$51.875 a t m$ $51.875 atm$

The,given relationship between pressure( $P$ $P$ ),volume( $V$ $V$ ) and temperature( $T$ $T$ ) of the gas is given as

$P \propto \frac{T}{V}$ $P prop T/V$

So,we can write, $P = k (\frac{T}{V})$ $P=k(T/V)$ (where, $k$ $k$ is a constant)

From the initial values of pressure,volume and temperature, we get, $k = 8.3$ $k=8.3$ $a t m l i t e r K^{- 1}$ $atm liter K^-1$

So, Final pressure will be $P' = k((T')/(V'))$

Given, $T'=500K , V'=80L$

So, $P'=8.3*(500/80) atm$ i.e $51.875 atm$