A 20.0 mL sample of a gas is at 546 K and has a pressure of 6.0 atm. If the temperature is changed to 273 K and the pressure to 2.0 atm, the new volume of the gas is what?

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A 20.0 mL sample of a gas is at 546 K and has a pressure of 6.0 atm. If the temperature is changed to 273 K and the pressure to 2.0 atm, the new volume of the gas is what?

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Answer 1 · 2016-12-15T18:41:47

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1=(P_2V_2)/T_2$ , given constant $n$ $n$ , so............

Explanation:

$V_{2} = \frac{P_{1} \times V_{1} \times T_{2}}{P_{2} \times T_{1}}$ $V_2=(P_1xxV_1xxT_2)/(P_2xxT_1)$

We immediately see that we will get an answer in $terms of volume$ $"terms of volume"$ , so we're batting on a firm wicket.

$V_{2} = \frac{6.0 \cdot a t m \times 20.0 \cdot m L \times 273 \cdot K}{2.0 \cdot a t m \times 546 \cdot K} = ? ? \cdot m L$ $V_2=(6.0*atmxx20.0*mLxx273*K)/(2.0*atmxx546*K)=??*mL$

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A 20.0 mL sample of a gas is at 546 K and has a pressure of 6.0 atm. If the temperature is changed to 273 K and the pressure to 2.0 atm, the new volume of the gas is what?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

A 20.0 mL sample of a gas is at 546 K and has a pressure of 6.0 atm. If the temperature is changed to 273 K and the pressure to 2.0 atm, the new volume of the gas is what?

1 Answer

Explanation:

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A 20.0 mL sample of a gas is at 546 K and has a pressure of 6.0 atm. If the temperature is changed to 273 K and the pressure to 2.0 atm, the new volume of the gas is what?