A ballerina spinning at 1.2 rev/sec with a moment of inertia of 2.6 kgm2 pulls her arms in so that her new moment of inertia is 1.8 kgm2. What is her new angular speed?

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A ballerina spinning at 1.2 rev/sec with a moment of inertia of 2.6 kgm2 pulls her arms in so that her new moment of inertia is 1.8 kgm2. What is her new angular speed?

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Answer 1 · 2015-09-23T13:06:30

$10, 891 r a d / s$ $10,891 rad//s$

Explanation:

Using the Principle of Conservation of Angular Momentum, we get :

$L_{1} = L_{2}$ $L_1 = L_2$
$therefore I_1omega_1=I_2omega_2$
$therefore omega_2=(I_1omega_1)/(I_2)=((2,6kg.m^2)(7,54rad//s))/(1,8kg.m^2)=10,891 rad//s$

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A ballerina spinning at 1.2 rev/sec with a moment of inertia of 2.6 kgm2 pulls her arms in so that her new moment of inertia is 1.8 kgm2. What is her new angular speed?

1 Answer

Explanation:

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