A charge of $12 C$ $12 C$ passes through a circuit every $3 s$ $3 s$ . If the circuit can generate $8 W$ $8 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-03-19T18:13:23

The resistance is $=2Omega$

We apply the following equation :

$P=RI^2$

Power, $P=8 W$

Current $=I$

Resistance $=R$

The current is related to the charge

$Q=It$

Charge, $Q=12C$

Time, $t=3s$

Current, $I=Q/t=12/3=4A$

Therefore,

The resistance is

$R=P/I^2=8/4^2=2 Omega$

A charge of 12 C12C12 C passes through a circuit every 3 s3s3 s. If the circuit can generate 8 W8W8 W of power, what is the circuit's resistance?