A charge of 12 C12C passes through a circuit every 9 s9s. If the circuit can generate 6 W6W of power, what is the circuit's resistance?

1 Answer
May 7, 2017

The resistance is =3.375 Omega

Explanation:

The charge is

Q=It

the current is I=Q/t

The power is

P=UI

But

According to Ohm's Law

U=RI

So,

the power is P=RI*I=RI^2

the resistance is R=P/I^2=P/(Q/t)^2

=6/(12/9)^2

=6*81/144

=3.375 Omega