A charge of $16 C$ $16 C$ passes through a circuit every $12 s$ $12 s$ . If the circuit can generate $9 W$ $9 W$ of power, what is the circuit's resistance?

Question

1230 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-03T15:07:57

I got $5Omega$

We can evaluate current as:

$I=Q/t$ i.e. the charge that passes in time.

With your data:

$I=16/12=1.3A$

Now, power is:

$P=VI$ that using Ohm's Law $V=RI$ can be written as:

$P=RI^2$

rearranging:

$R=P/I^2=9/1.3^2=5Omega$

A charge of 16 C16C16 C passes through a circuit every 12 s12s12 s. If the circuit can generate 9 W9W9 W of power, what is the circuit's resistance?