A charge of $16 C$ $16 C$ passes through a circuit every $12 s$ $12 s$ . If the circuit can generate $12 W$ $12 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-04-17T11:31:43

$6.75Omega$

Current is how much charge passes through a point per unit time, or

$I = Q/t$ .

In this case, the charge $Q=16C$ and the time is $t=12s$ , so

$I=16/12=4/3=1.33A$ .

Then you can solve for resistance by

$R=P/I^2$ .

Power is given in the question as $12W$ and $I$ we know is $4/3$ , so

$R=12/(16/9)=108/16=6.75Omega$

A charge of 16 C16C16 C passes through a circuit every 12 s12s12 s. If the circuit can generate 12 W12W12 W of power, what is the circuit's resistance?