A charge of $16 C$ $16 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $6 W$ $6 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-05-22T04:10:37

Resistance $R = 1.5 O h m s$ $R=1.5" ""Ohms$

From the given:
$q = 16 Coulomb$ $q=16" ""Coulomb"$
$t = 8 sec$ $t=8" ""sec"$

$P = 6 watts$ $P=6" ""watts"$

The current equation
$I = \frac{q}{t}$ $I=q/t$

$I = \frac{16}{8}$ $I=16/8$

$I = 2 Amp$ $I=2" ""Amp"$

The power equation

$P = I^{2} \cdot R$ $P=I^2*R$
$6 = {(2)}^{2} \cdot R$ $6=(2)^2*R$
$6 = 4 \cdot R$ $6=4*R$

$R = \frac{6}{4}$ $R=6/4$

$R = 1.5$ $R=1.5" "$ Ohms

God bless....I hope the explanation is useful.

A charge of 16C16 C passes through a circuit every 8s8 s. If the circuit can generate 6W6 W of power, what is the circuit's resistance?