A charge of $18 C$ passes through a circuit every $12 s$ . If the circuit can generate $12 W$ of power, what is the circuit's resistance?

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Answer 1 · 2018-05-23T12:41:25

The resistance is $=5.33Omega$

Apply the equation

$"Charge"(C)"$ $= "Current(A)"xx"time (t)"$

The charge is $Q=18C$

The time is $t=12s$

The current is $I=18/12=1.5A$

Ohm's Law states that

$U=RI$

The power is

$P=UI=RI^2$

The power is $P=12W$

The resistance is

$R=P/(I^2)=12/(1.5)^2=5.33Omega$

A charge of 18 C18 C passes through a circuit every 12 s12 s. If the circuit can generate 12 W12 W of power, what is the circuit's resistance?