A charge of $18 C$ passes through a circuit every $12 s$ . If the circuit can generate $1 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-04-14T09:35:12

$4/9 Omega$

The current through the circuit, $I= 18/12 Amp= 3/2 Amp$

We know Power, $P = I^2R$ , where R is the resistance.

Hence, $R = P/I^2 = (1 W)/(9/4 Amp^2) = 4/9 Omega$

A charge of 18 C18 C passes through a circuit every 12 s12 s. If the circuit can generate 1 W1 W of power, what is the circuit's resistance?