A charge of $18 C$ passes through a circuit every $2 s$ . If the circuit can generate $24 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-06-10T15:24:51

The resistance is $=0.296Omega$

The charge is related to the time and the current by the

$Q=It$ ^2=

The charge is $Q=18C$

The time is $t=2s$

The current is $I=Q/t=18/2=9A$

The power is

$P=UI$

But Ohm's Law states that

$U=RI$

So,

$P=RI^2$

Therefore,

$R=P/I^2=24/9^2=0.296Omega$

A charge of 18 C18 C passes through a circuit every 2 s2 s. If the circuit can generate 24 W24 W of power, what is the circuit's resistance?