A charge of $24 C$ $24 C$ passes through a circuit every $18 s$ $18 s$ . If the circuit can generate $8 W$ $8 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-05-11T17:50:21

$R = 4.5 O h m s$ $R=4.5" " Ohms$

$charge: q = 24 C$ $"charge: "q=24C$
$time : t = 18 s$ $"time : "t=18s$

$current: I = \frac{q}{t}$ $"current: "I=q/t$

$I = \frac{24}{18} = \frac{4}{3} A$ $I=24/18 =4/3A$

$power : P = I^{2} \cdot R$ $"power :"P=I^2*R$

$R = \frac{P}{I^{2}}$ $R=P/I^2$

$R = \frac{8}{{(\frac{4}{3})}^{2}}$ $R=8/(4/3)^2$

$R = 8 \cdot \frac{9}{16}$ $R=8*9/16$

$R = 4.5 O h m s$ $R=4.5" " Ohms$

A charge of 24C24 C passes through a circuit every 18s18 s. If the circuit can generate 8W8 W of power, what is the circuit's resistance?