A charge of 24 C24C passes through a circuit every 2 s2s. If the circuit can generate 3 W3W of power, what is the circuit's resistance?

1 Answer
Jun 23, 2017

The resistance is =21mOmega

Explanation:

The charge is related to the time and the current by the

Q=It

The charge is Q=24C

The time is t=2s

The current is I=Q/t=24/2=12A

The power is =3W

The power is

P=UI

But Ohm's Law states that

U=RI

So,

P=RI^2

Therefore,

R=P/I^2=3/12^2=0.021Omega