A charge of $24$ $C$ passes through a circuit every $4$ $s$ . If the circuit can generate $48$ $W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-04-28T10:38:26

The resistance of the circuit is $1.33$ $Omega$ .

The current in a circuit is the rate of flow of charge:

$I=(Delta Q)/t=(24C)/(4s)=6$ $A$

The power of an electric circuit is given by $P=I^2R$ .

Rearranging:

$R=P/I^2=(48W)/(6^2A^2)~~1.3$ $Omega$

A charge of 2424 CC passes through a circuit every 44 ss. If the circuit can generate 48 48 WW of power, what is the circuit's resistance?