A charge of $24 C$ $24 C$ passes through a circuit every $9 s$ $9 s$ . If the circuit can generate $32 W$ $32 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-02-07T17:22:23

$4.5Omega$

Electric current $I$ is the rate of flow of charge:

$I=Q/t=24/9=2.66"A"$

Power $P$ is given by:

$P=VxxI=32"W"$

So the voltage drop is given by:

$V=32/I=32/2.66=12"V"$

Using Ohm's Law:

$R=V/I=12/2.66=4.5Omega$

A charge of 24 C24C24 C passes through a circuit every 9 s9s9 s. If the circuit can generate 32 W32W32 W of power, what is the circuit's resistance?