A charge of $25 C$ $25 C$ passes through a circuit every $2 s$ $2 s$ . If the circuit can generate $25 W$ $25 W$ of power, what is the circuit's resistance?

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A charge of $25 C$ $25 C$ passes through a circuit every $2 s$ $2 s$ . If the circuit can generate $25 W$ $25 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-05-13T22:31:55

To find the resistance, we need to know voltage and current.

Explanation:

Current $I$ $I$ :
$I = \frac{25 C}{2 s} = 12.5 C / s = 12.5 A$ $I=(25C)/(2s)=12.5C//s=12.5A$

Voltage $U$ $U$
can be derived from power $p$ $p$ and current $I$ $I$ :
$p = U \times I \to U = \frac{p}{I} = \frac{25 W}{12.5 A} = 2 V$ $p=UxxI->U=p/I=(25W)/(12.5A)=2V$

Resistance $R$ $R$
$R=U/I=(2V)/(12.5A)=0.16Omega$

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A charge of $25 C$ $25 C$ passes through a circuit every $2 s$ $2 s$ . If the circuit can generate $25 W$ $25 W$ of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of 25 C25C25 C passes through a circuit every 2 s2s2 s. If the circuit can generate 25 W25W25 W of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of $25 C$ $25 C$ passes through a circuit every $2 s$ $2 s$ . If the circuit can generate $25 W$ $25 W$ of power, what is the circuit's resistance?