A charge of $27 C$ $27 C$ passes through a circuit every $3 s$ $3 s$ . If the circuit can generate $63 W$ $63 W$ of power, what is the circuit's resistance?

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A charge of $27 C$ $27 C$ passes through a circuit every $3 s$ $3 s$ . If the circuit can generate $63 W$ $63 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-04-15T06:06:03

First step: $I = \frac{Q}{t} = \frac{27}{3} = 9$ $I=Q/t=27/3=9$ $A$ $A$
Second step: $P = I^{2} R \to R = \frac{P}{I^{2}} = \frac{63}{9^{2}} \approx 0.78$ $P=I^2R to R=P/I^2=63/9^2~~0.78$ $Omega$

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A charge of $27 C$ $27 C$ passes through a circuit every $3 s$ $3 s$ . If the circuit can generate $63 W$ $63 W$ of power, what is the circuit's resistance?

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A charge of 27 C27C27 C passes through a circuit every 3 s3s3 s. If the circuit can generate 63 W63W63 W of power, what is the circuit's resistance?

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A charge of $27 C$ $27 C$ passes through a circuit every $3 s$ $3 s$ . If the circuit can generate $63 W$ $63 W$ of power, what is the circuit's resistance?