A charge of 27 C passes through a circuit every 3 s. If the circuit can generate 72 W of power, what is the circuit's resistance?

1 Answer
Apr 8, 2016

R=8/9 Ohm

Explanation:

"given data:"
q=27C" charge"
Delta t=3 s" time interval"
P=72W" Power"
R=?" Resistance"

so" " P=I^2*R

"we must calculate the electric current I"
I=(Delta q)/(Delta t)

I=27/3=9A

cancel(72)=cancel(9)^2*R

8=9*R

R=8/9 Ohm