A charge of 30 C30C passes through a circuit every 5 s5s. If the circuit can generate 42 W42W of power, what is the circuit's resistance?

1 Answer
May 25, 2016

R=1.17" " Omega

Explanation:

I=(Delta Q)/(Delta t)" The electric current passing through circuit"

Delta Q=30C
Delta t=5s

I=30/5=6A

P=I^2*R

"P:Power"
"R:resistance"

42=6^2*R

42=36*R

R=42/36

R=1.17" " Omega