A charge of $30 C$ passes through a circuit every $5 s$ . If the circuit can generate $42 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-05-08T18:14:14

$R= 7/6Omega$

Current is charge divided by time:

$I = (30"C")/(5"s") = 6"A"$

Power it the square of the current multiplied by the resistance:

$P = I^2R$

$42"W" = (6"A")^2R$

$R= 42/36Omega$

$R= 7/6Omega$

A charge of 30 C30 C passes through a circuit every 5 s5 s. If the circuit can generate 42 W42 W of power, what is the circuit's resistance?