A charge of 35 C35C passes through a circuit every 5 s5s. If the circuit can generate 12 W12W of power, what is the circuit's resistance?

1 Answer
Nov 4, 2016

12/491249 Ohms

Explanation:

The relationship between power P, voltage V, and current I is

P = IV = I^2 RP=IV=I2R as V = IRV=IR from Ohm's Law

So R = P/I^2R=PI2

We know also that current is the rate of flow of charge, so I = (Delta q)/(Delta t)

This means

R = ( P )/( (Delta q)/(Delta t))^2 = ( 12 )/( (35)/(5))^2 = 12/49 \ Omega