A charge of 3535 CC passes through a circuit every 55 ss. If the circuit can generate 77 WW of power, what is the circuit's resistance?

1 Answer
Feb 15, 2016

Convert the flow of charge into current, then use and rearrange P=I^2RP=I2R to find that the resistance is 1/717 Omega.

Explanation:

Current is defined as the rate of flow of charge:

I=Q/t=35/5=7 A

The power in a circuit can be expressed as:

P=I^2R

(Combining the equation P=VI with Ohm's Law, V=IR will yield this.)

Rearranging:

R = P/I^2=7/7^2=1/7 Omega