A charge of $35 C$ $35 C$ passes through a circuit every $5 s$ $5 s$ . If the circuit can generate $82 W$ $82 W$ of power, what is the circuit's resistance?

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Answer 1 · 2018-05-15T13:05:08

$1.67$ $1.67$ ohms

We first find the current produced, which is given by the equation,

$I = \frac{Q}{t}$ $I=Q/t$

where:

$I$ $I$ is the current in amperes

$Q$ $Q$ is the charge in coulombs

$t$ $t$ is the time in seconds

So here, we get:

$I=(35 \ "C")/(5 \ "s")=7 \ "A"$

Then, power is given through the equation:

$P=I^2R \ (because V=IR \ "and" \ P=IV)$

where:

$P$ is the power in watts

$R$ is the resistance in ohms

So, we get:

$82 \ "W"=(7 \ "A")^2*R$

$R=(82 \ "W")/(49 \ "A"^2)$

$=1.67 \ Omega$

A charge of 35 C35C35 C passes through a circuit every 5 s5s5 s. If the circuit can generate 82 W82W82 W of power, what is the circuit's resistance?