Question

A charge of `36 C` passes through a circuit every `9 s`. If the circuit can generate `16 W` of power, what is the circuit's resistance?

Answer 1

`R = 1 Omega`

Explanation:

`I = (36 C)/(9 s) = 4` Amperes

`P = I^2R`

`R = (16 W)/(4^2A) = 1 Omega`