A charge of $40 C$ $40 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $34 W$ $34 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-07-01T06:05:05

1.36 ohm

Current $I = \frac{q}{t}$ $I=q/t$

$q = 40 C$ $q=40C$
$t = 8 s$ $t=8s$

Therefore $I = 5 A$ $I=5A$

Power $P = I^{2} R$ $P=I^2 R$

$P = 34 W$ $P=34W$
Substituting the value of $I^{2}$ $I^2$
We get $R = 1.36 o h m$ $R=1.36 ohm$

A charge of 40 C40C40 C passes through a circuit every 8 s8s8 s. If the circuit can generate 34 W34W34 W of power, what is the circuit's resistance?