A charge of $40 C$ $40 C$ passes through a circuit every $8 s$ $8 s$ . If the circuit can generate $35 W$ $35 W$ of power, what is the circuit's resistance?

Question

1441 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-14T07:57:09

I got $1.4Omega$

You can evaluate the current as:
$I=Q/t=40/8=5A$

Power can be written as: $P=VI$

Using Ohm's Law: $V=RI$ we write:

$P=I^2R$

Rearranging:

$R=P/I^2=35/25=1.4Omega$

A charge of 40 C40C40 C passes through a circuit every 8 s8s8 s. If the circuit can generate 35 W35W35 W of power, what is the circuit's resistance?