A charge of $45 C$ $45 C$ passes through a circuit every $6 s$ $6 s$ . If the circuit can generate $98 W$ $98 W$ of power, what is the circuit's resistance?

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A charge of $45 C$ $45 C$ passes through a circuit every $6 s$ $6 s$ . If the circuit can generate $98 W$ $98 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-09-15T13:38:59

The resistance is 1.742 $Omega$

Explanation:

The current in the circuit is the amount of charge that passes by a point per second. It is found from the equation $I = (Delta Q)/(Delta t)= (45 C)/(6 s) = 7.5 A$ .

The power in a circuit is found from the equation $P = IV = I^2R$ . This means that the resistance is $R = (P)/(I^2) = (98 W)/(7.5 A)^2 = 1.742 Omega$

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A charge of $45 C$ $45 C$ passes through a circuit every $6 s$ $6 s$ . If the circuit can generate $98 W$ $98 W$ of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of 45 C45C45 C passes through a circuit every 6 s6s6 s. If the circuit can generate 98 W98W98 W of power, what is the circuit's resistance?

1 Answer

Explanation:

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A charge of $45 C$ $45 C$ passes through a circuit every $6 s$ $6 s$ . If the circuit can generate $98 W$ $98 W$ of power, what is the circuit's resistance?