A charge of $5 C$ passes through a circuit every $2 s$ . If the circuit can generate $15 W$ of power, what is the circuit's resistance?

Question

1710 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-06T21:53:38

The resistance is $2.4 Omega$

A rate of charge movement that causes 5C of charge to pass every 2 s is a current of 2.5 A

$I=Q/t = (5 C)/(2 s) = 2.5 C/s or 2.5 A$

Next we use the relation

$P=I^2R$ to find the resistance

Write this as

$R=P/I^2 = (15W)/(2.5A)^2 = 2.4 Omega$

Answer 2 · 2017-11-06T21:54:24

$2.4 Omega$

$C = It$
charge = current * time

$I = C/t = 5/2A$
current = charge/time

$P = I^2R$
power = current^2 * resistance

$15W = (5/2)^2 * R$

$15W = 6.25 * R$

$R = 15/6.25 Omega$

$= 60/25 = 12/5$

$=2.4 Omega$

A charge of 5 C5 C passes through a circuit every 2 s2 s. If the circuit can generate 15 W15 W of power, what is the circuit's resistance?