A charge of $5 C$ $5 C$ passes through a circuit every $2 s$ $2 s$ . If the circuit can generate $25 W$ $25 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-05-07T11:28:14

$=4Omega$

We know
$"Current"(I)=("Charge passed"(q))/("Time"(t))=5/2A=2.5A$
Again
$Power(P)=I^2xxR$
Therefore Resistance $R =P/I^2=25/2.5^2=4Omega$

A charge of 5 C5C5 C passes through a circuit every 2 s2s2 s. If the circuit can generate 25 W25W25 W of power, what is the circuit's resistance?