Question

A charge of `5 C` passes through a circuit every `5 s`. If the circuit can generate `15 W` of power, what is the circuit's resistance?

Answer 1

`R = 15 Omega`

Explanation:

`(5 C)/(5 s) = 1` ampere

`P = I²R`

`15 W = (1 A)`R

`R = 15 Omega`