A charge of $54 C$ passes through a circuit every $6 s$ . If the circuit can generate $98 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-07-15T12:59:50

$R = 1.21Omega$

$I=(dQ)/(dt)$ will give momentary current, but as the current is constant

$I=(DeltaQ)/(Deltat) = (54C)/(6s) = 9A$

$P = I^2R implies R = P/I^2$

$R = (98W)/(81A^2) = 1.21Omega$

A charge of 54 C54 C passes through a circuit every 6 s6 s. If the circuit can generate 98 W98 W of power, what is the circuit's resistance?