A charge of $54 C$ passes through a circuit every $6 s$ . If the circuit can generate $63 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-05-10T23:53:43

I found $0.66Omega$

You know that current $I$ is:
$I=q/t=54/6=9A$
We can now use the fact that power is:
$P=VI=I^2R$
Rearranging:
$R=P/I^2=63/9^2=0.66Omega$

A charge of 54 C54 C passes through a circuit every 6 s6 s. If the circuit can generate 63 W63 W of power, what is the circuit's resistance?