A charge of 6 C6C passes through a circuit every 3 s3s. If the circuit can generate 18 W18W of power, what is the circuit's resistance?

1 Answer

4.5\ \Omega

Explanation:

The electric current I is the rate of flow of charge w.r.t. time which given as

I={dQ}/{dt}

=\frac{6}{3}

=2\ A

If R\ \Omega is the electric resistance then the electric power or rate of heat generation is given by Joule's Law as follows

H=I^2R

18=2^2R\quad (\because \ H=18\ W)

R=18/4

R=4.5

Hence the electric resistance is R=4.5\ \Omega