A charge of $6 C$ passes through a circuit every $3 s$ . If the circuit can generate $36 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-04-15T06:29:20

The resistance is $=9Omega$

The charge and the the current are related by the equation

$I=Q/t$

$I=6/3=2A$

We need the equation

$U=RI$

and

$P=UI=RI^2$

Therefore,

$R=P/I^2=36/2^2=9Omega$

A charge of 6 C6 C passes through a circuit every 3 s3 s. If the circuit can generate 36 W36 W of power, what is the circuit's resistance?