A charge of $6 C$ $6 C$ passes through a circuit every $3 s$ $3 s$ . If the circuit can generate $4 W$ $4 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-01-01T00:52:32

$The current in the circuit (I) = \frac{Charge passing through it}{Time}$ $"The current in the circuit"(I)="Charge passing through it"/"Time"$

$= \frac{6 C}{3 s} = 2 A$ $=(6C)/(3s)=2A$

Now $Power (P) = I^{2} \times R$ $"Power" (P)=I^2xxR$ , where R = Resistance

So $R=P/I^2=4/2^2=1Omega$

A charge of 6 C6C6 C passes through a circuit every 3 s3s3 s. If the circuit can generate 4 W4W4 W of power, what is the circuit's resistance?