A charge of 8 C8C passes through a circuit every 12 s12s. If the circuit can generate 12 W12W of power, what is the circuit's resistance?

1 Answer
Mar 14, 2016

R=27" " OhmR=27 Ohm

Explanation:

I=(Delta Q)/(Delta t)" Electric Current"
I=8/12=2/3 A
P=I^2*R" P:Power;R:Resistance;I:Electric Current"
12=(2/3)^2*R
cancel(12)=cancel(4)/9.R
3=R/9
R=3*9
R=27" " Ohm