A charge of 8 C8C passes through a circuit every 2 s2s. If the circuit can generate 3 W3W of power, what is the circuit's resistance?

1 Answer
Dec 19, 2016

I found: 0.2Omega

Explanation:

You know that current I is the rate of passing of charge Q through a section of a conductor with time t or:

I=Q/t

in your case:
I=8/2=4A

Power P is the rate of transformation of energy with time that, in case of electrical circuits, can be written (using also Ohm's Law: V=RI):

P=VI=V^2/R=I^2R

using the last one:

P=I^2R and rearranging:

R=P/I^2=3/4^2=3/16=0.1875~~0.2Omega