A circle has the equation ${(x + 1)}^{2} + {(y - 3)}^{2} = 16$ $(x + 1)^2 + (y - 3)^2 = 16$ . What are the coordinates of its center and length of radii?

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A circle has the equation ${(x + 1)}^{2} + {(y - 3)}^{2} = 16$ $(x + 1)^2 + (y - 3)^2 = 16$ . What are the coordinates of its center and length of radii?

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Answer 1 · 2016-01-22T11:03:25

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Explanation:

You can think at the general equation of a circle:
${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$
where:
$h, k$ $h,k$ are the coordinates of the center;
$r$ $r$ is the radius.

In your case:

$h = - 1$ $h=-1$
$k = 3$ $k=3$
$r = \sqrt{16} = 4$ $r=sqrt(16)=4$

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A circle has the equation ${(x + 1)}^{2} + {(y - 3)}^{2} = 16$ $(x + 1)^2 + (y - 3)^2 = 16$ . What are the coordinates of its center and length of radii?

1 Answer

Explanation:

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Science

Math

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A circle has the equation (x+1)2+(y−3)2=16(x + 1)^2 + (y - 3)^2 = 16. What are the coordinates of its center and length of radii?

1 Answer

Explanation:

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A circle has the equation ${(x + 1)}^{2} + {(y - 3)}^{2} = 16$ $(x + 1)^2 + (y - 3)^2 = 16$ . What are the coordinates of its center and length of radii?