A circle has the equation $(x + 1)^2 + (y - 3)^2 = 16$ . What are the coordinates of its center and length of radii?

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Answer 1 · 2016-01-22T11:03:25

Have a look:

You can think at the general equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
where:
$h,k$ are the coordinates of the center;
$r$ is the radius.

In your case:

$h=-1$
$k=3$
$r=sqrt(16)=4$

A circle has the equation (x + 1)^2 + (y - 3)^2 = 16(x + 1)^2 + (y - 3)^2 = 16. What are the coordinates of its center and length of radii?