A container with a volume of #13 L# contains a gas with a temperature of #130^o C#. If the temperature of the gas changes to #420 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-06-22T06:27:34

The new volume is #=13.5L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=13L#

The initial temperature is #T_1=130+273=403K#

The final temperature is #T_2=420K#

The final volume is

#V_2=T_2/T_1*V_1#

#=420/403*13=13.5L#